How do you solve $(3x)/(x+1)=12/(x^2-1)+2$ ?

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Answer 1 · 2017-09-23T12:30:38

Solution: $x=5 , x= -2$

$(3x)/(x+1)= 12/(x^2-1) +2$ or

$(3x)/(x+1) -12/(x^2-1) = 2$ Multiplying by $(x^2-1)$ on both

sides we get $3x(x-1) -12 = 2 (x^2-1)$ or

$3x^2-3x -12 = 2x^2-2$ or

$x^2-3x = 10 or x^2 -3x +9/4 = 10 +9/4 ; (9/4)$ is added

on both side to make L.H.S a square.

$(x-3/2)^2 = 49/4 or x-3/2 = +- sqrt (49/4)$ or

$x-3/2 = +- 7/2 :. x =3/2 +- 7/2 or x = 1/2( 3+-7) :.$

$x=5 , x= -2$ . Solution: $x=5 , x= -2$ [Ans]

How do you solve (3x)/(x+1)=12/(x^2-1)+2(3x)/(x+1)=12/(x^2-1)+2?