How do you solve #-3x+5y=-10# and #-3x+6y=-12#?

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Answer 1 · 2018-05-14T14:32:05

#x=20/3# and #y=2#

Take equation #-3x+6y=-12# and subtract #-3x+5y=-10#

#-3x + 6y = -12#
#-3x + 5y = -10#

#0x + y = 2 => y=2#

put #y=2# into the first equation

#=> -3x + 5 xx 2 = -10#

#-3x+10=-10#

#-3x=-20#

#x=20/3#