How do you solve $|3x + 2| = 14$ ?

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Answer 1 · 2016-03-14T14:21:47

$x=4,-16/3$

$color(blue)(|\3x+2|=14$

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$:.$ Absolute value is always positive

Eg. $|6-7|=1$

But $|6-7|$ actually equals $1$ and $-1$

So, $|\3x+2|=14,-14$

Solve for the first value

$rarr3x+2=14$

$rarr3x=14-2$

$rarr3x=12$

$rArrcolor(green)(x=12/3=4$

Then, solve for the second value

$rarr3x+2=-14$

$rarr3x=-14-2$

$rarr3x=-16$

$rArrcolor(green)(x=-16/3$

How do you solve |3x + 2| = 14|3x + 2| = 14?