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How do you solve #-3x + 2 >11# or #5(x - 2) <0#?

1 Answer

Jul 13, 2017

Solution : # x < -3 # , in interval notation : # (-oo, -3)#

Explanation:

1) # -3x +2 > 11 or -3x > 9 or -x > 3 or x < -3 #

2) # 5 (x-2) < 0 or x-2 < 0 or x < 2#

# x < -3 # satisfies both inequaity.

Solution : # x < -3 # , in interval notation : # (-oo, -3)# [Ans]

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