How do you solve #-3x + 2 >11# or #5(x - 2) <0#? Algebra Linear Inequalities and Absolute Value Compound Inequalities 1 Answer Binayaka C. Jul 13, 2017 Solution : # x < -3 # , in interval notation : # (-oo, -3)# Explanation: 1) # -3x +2 > 11 or -3x > 9 or -x > 3 or x < -3 # 2) # 5 (x-2) < 0 or x-2 < 0 or x < 2# # x < -3 # satisfies both inequaity. Solution : # x < -3 # , in interval notation : # (-oo, -3)# [Ans] Answer link Related questions How do you solve compound inequalities? What is an example of an inequality that uses "and" and what inequality uses "or"? How do you graph #-40 \le y < 60# on a number line? How do you solve for x in #3x-5 < x + 9 \le 5x + 13 #? How do you solve #9-2x \le 3 or 3x+10 \le 6-x#? How do you solve for b given #6+b<8 or b+6 \ge 6#? How do you graph #x ≥ 4# or #x > -4#? How do you solve the compound inequality #-20≤-6m-2≤58# and graph its solution? How do you graph #-53<9v+1<-26#? How do you graph this inequality: #15<x<30#? See all questions in Compound Inequalities Impact of this question 1803 views around the world You can reuse this answer Creative Commons License