# How do you solve 3Log_5 x - Log_5 4 = Log_5 16?

Jun 15, 2016

$x = 4$

#### Explanation:

$3 {\log}_{5} x - {\log}_{5} 4 = {\log}_{5} 16$

or ${\log}_{5} {x}^{3} - {\log}_{5} 4 = {\log}_{5} 16$

or ${\log}_{5} {x}^{3} / 4 = {\log}_{5} 16$

or ${x}^{3} / 4 = 16$

or ${x}^{3} = 64$

or $x = 4$