How do you solve #3log_4 n= 6 #?

1 Answer
reudhreghs
Apr 4, 2016

#n = 16#

Explanation:

Begin with dividing both sides by three to make it much easier to approach.

#4log_4n = 6#
#log_4n = 2#

Now raise both sides to the power of 4, which will cancel out the logarithm

#log_4n = 2#
#4^(log_4n) = 4^2#
#n = 4^2#
#n = 16#

Related questions
See all questions in Common Logs
Impact of this question
1183 views around the world
You can reuse this answer
Creative Commons License