How do you solve #3lnx+ln5=7#?

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Answer 1 · 2015-11-26T18:44:22

Use the properties of logs ...

#3lnx+ln5=ln[(5)(x^3)]#

Now, exponentiate both sides of the equation ...

#e^ln[(5)(x^3)]=e^7#

Simplify and solve for x...

#5x^3=e^7#

#x^3=(e^7)/5#

#(x^3)^(1/3)=x=[(e^7)/5]^(1/3)~~6.031#

hope that helped

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