How do you solve $\frac{3 k}{27} = \frac{2}{3}$ $(3k)/27=2/3$ ?

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How do you solve $\frac{3 k}{27} = \frac{2}{3}$ $(3k)/27=2/3$ ?

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Answer 1 · 2017-03-12T23:10:21

See the entire solution process below:

Explanation:

Multiply each side of the equation by $\frac{27}{3}$ $color(red)(27)/color(blue)(3)$ to solve for $k$ $k$ while keeping the equation balanced:

$\frac{27}{3} \times \frac{3 k}{27} = \frac{27}{3} \times \frac{2}{3}$ $color(red)(27)/color(blue)(3) xx (3k)/27 = color(red)(27)/color(blue)(3) xx 2/3$

$cancel(color(red)(27))/cancel(color(blue)(3)) xx (color(blue)(cancel(color(black)(3)))k)/color(red)(cancel(color(black)(27))) = (color(red)(27) xx 2)/(color(blue)(3) xx 3)$

$k = (color(red)(27) xx 2)/9$

$k = (cancel(color(red)(27))3 xx 2)/color(red)(cancel(color(black)(9)))$

$k = 6$

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How do you solve $\frac{3 k}{27} = \frac{2}{3}$ $(3k)/27=2/3$ ?

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