How do you solve #3e^x=122#?

1 Answer
Jun 9, 2016

Using the logarithm.

Explanation:

The way to "pull down" the #x# from an exponential is to use the inverse function that is the logarithm.

#3e^x=122#

#e^x=122/3#

Then we apply the logarithm on both sides

#ln(e^x)=ln(122/3)#

Because the logarithm is the inverse of the exponential, they cancel each other on the left

#x=ln(122/3)\approx3.7#.