How do you solve #3abs(2x-5)=39#?

2 Answers
Vincent
May 24, 2018

x=-4 or x=9

Explanation:

lets find first where #2x-5=0# the answer to that is #x=2.5#
If #x >2.5# then #2x-5>0# so the ansolute value is #3(2x-5)=39#
If #x<2.5# then #2x-5<0# so the absolute value is #3(5-2x)=39#
So it gives u different solutions in the first case where the #x>2.5# is #6x-15=39=>6x=54=>x=9#
In the secont case where #x<2.5 its 15-6x=39=>6x=-24=>x=-4#

Michael · Stefan V.
May 24, 2018

#x=9 or x=-4#

Explanation:

Well, we can divide the #3# out to get

#|2x−5|=13#

Now we know that #2x-5# must equal #13# or #-13# because it is the absolute value. We set #2x-5# equal to #13# and #-13# and solve for #x#.

So

#2x-5+5=13+5#

#2x=18#

Divide both sides by #2# and get

#x=9#

Also

#2x-5+5=-13+5#

#2x=-8#

Divide both sides by #2# and get

#x=-4#

There you have it. #x=9# or #x=-4#.

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