# How do you solve 36^ (x + 2) = 6 ^(4x) ?

Apr 5, 2016

$x = 2$

#### Explanation:

$1$. Knowing that $36 = {6}^{2}$, simplify ${36}^{x + 2}$.

${36}^{x + 2} = {6}^{4 x}$

${6}^{2 \left(x + 2\right)} = {6}^{4 x}$

${6}^{2 x + 4} = {6}^{4 x}$

$2$. Since the powers both have the same base on either side of the equation, the exponents are equal to each other.

$2 x + 4 = 4 x$

$3$. Solve for $x$.

$2 x = 4$

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