How do you solve #36^ (x + 2) = 6 ^(4x) #?

1 Answer
Johnson Z.
Apr 5, 2016

#x=2#

Explanation:

#1#. Knowing that #36=6^2#, simplify #36^(x+2)#.

#36^(x+2)=6^(4x)#

#6^(2(x+2))=6^(4x)#

#6^(2x+4)=6^(4x)#

#2#. Since the powers both have the same base on either side of the equation, the exponents are equal to each other.

#2x+4=4x#

#3#. Solve for #x#.

#2x=4#

#color(green)(|bar(ul(color(white)(a/a)x=2color(white)(a/a)| )))#

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