How do you solve #-36= - 32t#?

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Answer 1 · 2017-03-26T21:44:56

#t = 9/8#

We want the value of t so we have to divide both sides by #-32# so that #t# stands alone

#(-36)/(-32# = #cancel(-32t)/cancel(-32)#

#t = (36)/(32)#

Dividing the numerator and denominator by 4, we get

#t = 9/8#

Or #t=36/32=(4*9)/(4*8)=(cancel(4)*9)/(cancel(4)*8)#

#:.t=9/8#