How do you solve #32^(5p+2)>=16^(5p)#?
1 Answer
Mar 10, 2018
Explanation:
Rewrite in powers of
#(2^5)^(5p + 2) ≥ (2^4)^(5p)#
#2^(25p + 10) ≥ 2^(20p)#
#25p + 10 ≥ 20p#
#5p ≥ -10#
#p ≥ -2#
Hopefully this helps!
