How do you solve #3/(z+7)=2/(z-4)#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Veddesh #phi# Mar 17, 2016 #z=26# Explanation: #color(blue)(3/(z+7)=2/(z-4)# Cross multiply #color(brown)(a/b=c/d,ad=bc# #rarr3(z-4)=2(z+7)# Use distributive property #color(brown)(a(b+c)=ab+ac# #rarr3z-12=2z+14# #rarr3z-2z=14+12# #rarrz=14+12# #color(green)(rArrz=26# Check #color(indigo)(3/(26+7)=2/(26-4)# #color(indigo)(3/33=2/22# #color(indigo)(1/11=1/11# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1332 views around the world You can reuse this answer Creative Commons License