How do you solve #3^x = 7#?

1 Answer
Apr 3, 2016

x ≈ 1.77

Explanation:

Using the following ' rule of logs '

#• logx^n = nlogx #

Take log of both sides. We can use log to any base. I'll use ln which is the # log_e#

hence # ln3^x = ln7 #

using the rule from above : # xln3 = ln7 → x = ln7/ln3 ≈ 1.77 #