How do you solve 3^x = 7?

Apr 3, 2016

x ≈ 1.77

Explanation:

Using the following ' rule of logs '

• logx^n = nlogx

Take log of both sides. We can use log to any base. I'll use ln which is the ${\log}_{e}$

hence $\ln {3}^{x} = \ln 7$

using the rule from above :  xln3 = ln7 → x = ln7/ln3 ≈ 1.77