How do you solve #3/(x+3) - 4/(x-3) = (5x)/(x^2-9)#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Alan N. Aug 3, 2016 #x=-7/2# Explanation: #3/(x+3) - 4/(x-3) = (5x)/(x^2-9)# #(3(x-3)-4(x+3))/(x^2-9) = (5x)/(x^2-9)# For #x!= +-3#: #(3(x-3)-4(x+3))/cancel(x^2-9) = (5x)/cancel(x^2-9)# #3(x-3)-4(x+3) = 5x# #3x-9-4x-12 = 5x# #-6x=21# #x=-7/2# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 6356 views around the world You can reuse this answer Creative Commons License