# How do you solve 3^(x+1) * 2^(x-2)= 21?

Nov 15, 2015

Use law of exponents to simplify

#### Explanation:

${3}^{x} 3 \times {2}^{x} / {2}^{2} = 21$

${\left(3 \times 2\right)}^{x} \left(\frac{3}{4}\right) = 21$

${6}^{x} = 28$

Next, use the property of logs ...

$x \log 6 = \log 28$

$x = \log \frac{28}{\log} 6 \approx 1.86$

hope that helped