How do you solve #3^(x+1)=15#?

1 Answer
George C.
Apr 27, 2016

#x = log 5/log 3 ~~ 1.465#

Explanation:

First note that #3^(x+1) = 3*3^x#, so we can divide both sides of the equation by #3# to get:

#3^x = 5#

Taking logs of both sides (any base), we get:

#x log 3 = log 5#

Hence:

#x = log 5 / log 3 ~~ 1.465#

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