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How do you solve #3^(n-2)=27#?

1 Answer

Shwetank Mauria

Oct 13, 2016

#n=5#

Explanation:

As #3^(n-2)=27#

converting it into logarithmic form, we have

#log_3 27=n-2#

But #log_3 27=log_3 3^3=3log_3 3=3xx1=3#

Hence #n-2=3#

and #n=3+2=5#

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