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How do you solve #3=log_x125 #?

1 Answer

Apr 19, 2016

#x=5#

Explanation:

#3=log_x125#

#3=log_x 5^3#

#3=3*log_x 5#

#3/3=log_x 5#

#log_x 5=1#

#so ; x^1=5#

#x=5#

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