How do you solve #3 log_5 x - log_5 4 = log_5 16#?
The answer is
To solve this equation you have to use the facts that:
#a*log_b(c)=log_b(c^a)# #log_a(b)-log_a(c)=log_a (b/c)#
First you use (1) to get:
Then you use (2) to get:
Now you can leave the logarithms (they both have the same base)