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How do you solve #3 log_2 (x-1)=5 - log_2 (4) #?

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1 Answer

Konstantinos Michailidis

Dec 28, 2015

It is #x=3#

Explanation:

It is

#3 log_2 (x-1)=5 - log_2 (4)=>log_2(x-1)^3+log_2 4=5=> log_2(4*(x-1)^3)=5=>4*(x-1)^3=2^5=>(x-1)^3=2^3=>x-1=2=>x=3 #

Of course from the definition of the logarithm is

#x-1>0=x>1#

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