How do you solve $3(abs(x-1)+2)=30$ ?

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Answer 1 · 2015-05-10T17:42:58

The solutions are $x = -7$ and $x = 9$ .

Starting with $3(|x-1|+2)=30$ , first divide both sides by 3 to give:
$|x-1|+2=10$ .

Subtract 2 from both sides to give:
$|x-1|=8$

Hence
$x-1=+-8$

Add 1 to both sides to get:
$x = +-8 + 1$

So $x=-8+1=-7$ or $x=8+1=9$ .

How do you solve 3(abs(x-1)+2)=303(abs(x-1)+2)=30?