How do you solve #3 > abs(a + 1)#?
1 Answer
Jun 2, 2015
or
Thus :
#3>a+1#
#3-1>a# ( we substract 1 on each side )
# 2>a#
#a<2#
Or :
#3> -a-1#
#3+1> -a# ( we add 1 on each side )
#4> -a#
# -4< a# ( we multiply by#-1# on each side, and thus#># becomes#<# )
# a> -4#
