How do you solve $3-abs(8x-6)=3$ ?

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Answer 1 · 2017-04-17T08:00:51

$x=3/4$

We have
$|8x-6|=3-3=0$
but the only number with absolute value $0$ is $0$ , so we can drop the absolute value and get $8x-6=0$ , hence $x=3/4$

How do you solve 3-abs(8x-6)=33-abs(8x-6)=3?