How do you solve $3 - 5abs(2d - 3) = 4$ ?

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Answer 1 · 2015-07-23T17:26:52

$d in emptyset$

$3-4 = 5|2d−3|$

$0 > -1/5 = |2d−3|$

What is the number whose modulus is negative? None.

How do you solve 3 - 5abs(2d - 3) = 43 - 5abs(2d - 3) = 4?