How do you solve $\frac{3}{5} = \frac{y + 1}{9}$ $3/5=(y+1)/9$ ?

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How do you solve $\frac{3}{5} = \frac{y + 1}{9}$ $3/5=(y+1)/9$ ?

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Answer 1 · 2016-08-04T17:43:34

$y = \frac{22}{5}$ $y=22/5$

Explanation:

$\frac{3}{5} = \frac{y + 1}{9}$ $3/5=(y+1)/9$
or
$y + 1 = (\frac{3}{5}) 9$ $y+1=(3/5)9$
or
$y + 1 = \frac{27}{5}$ $y+1=27/5$
or
$y = \frac{27}{5} - 1$ $y=27/5-1$
or
$y = \frac{22}{5}$ $y=22/5$

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How do you solve $\frac{3}{5} = \frac{y + 1}{9}$ $3/5=(y+1)/9$ ?

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How do you solve $\frac{3}{5} = \frac{y + 1}{9}$ $3/5=(y+1)/9$ ?