How do you solve 3 ^(-4x+4) = 9? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer ali ergin May 23, 2016 x=1/2 Explanation: 3^(-4x+4)=9 3^(-4x) *3^4=3^2 3^(-4x)=(3^2)/(3^4) 3^(-4x)=3^2*3^-4 color(red)(3)^(-4x)=color(red)(3)^-2 "Both side of equation has the same base value" -4x=-2 x=2/4 x=1/2 Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve 9^(x-4)=81? How do you solve logx+log(x+15)=2? How do you solve the equation 2 log4(x + 7)-log4(16) = 2? How do you solve 2 log x^4 = 16? How do you solve 2+log_3(2x+5)-log_3x=4? See all questions in Logarithmic Models Impact of this question 1289 views around the world You can reuse this answer Creative Commons License