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How do you solve #3^(2x+5)=27^x#?

1 Answer

Dec 6, 2015

#x=5#

Explanation:

Using laws of exponents we may write this equation as

#3^(2x)*3^5=3^(3x)#

#therefore3^5=3^(3x-2x)#

#therefore 3^5=3^x# and hence #x=5#

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