# How do you solve 3^(2x-3) = 27sqrt3?

Dec 6, 2015

$x = 3 , 25$

#### Explanation:

Using laws of exponents we may write this equation as

${3}^{2 x} \cdot {3}^{- 3} = {3}^{3} \cdot {3}^{\frac{1}{2}}$

$\therefore 2 x - 3 = 3 + \frac{1}{2}$

$\therefore x = \frac{6 , 5}{2} = 3 , 25$