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How do you solve #3^(2x-3) = 27sqrt3#?

1 Answer

Dec 6, 2015

#x=3,25#

Explanation:

Using laws of exponents we may write this equation as

#3^(2x)*3^(-3)=3^3*3^(1/2)#

#therefore2x-3=3+1/2#

#thereforex=(6,5)/2=3,25#

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