How do you solve $\frac{3}{2 k + 1} = \frac{2}{9}$ $3/(2k+1)=2/9$ ?

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Answer 1 · 2018-07-28T20:39:20

$k = \frac{25}{4}$ $k=25/4$

We can cross multiply to now have the equation

$3 (9) = 2 (2 k + 1)$ $3(9)=2(2k+1)$ , which simplifies to

$27 = 4 k + 2$ $27=4k+2$

To get our $k$ $k$ terms on one side, let's subtract $2$ $2$ from both sides to get

$4 k = 25$ $4k=25$

Lastly, let's divide both sides by $4$ $4$ to get

$k = \frac{25}{4}$ $k=25/4$

Hope this helps!

How do you solve 32k+1=293/(2k+1)=2/9?