How do you solve #3(2)^(x-2)+1=100#?

1 Answer
Zor Shekhtman
Oct 8, 2015

#x = log_2(33)+2#

Explanation:

As it is written, the answer does not look well rounded.
Here is the solution of the original equation
#3*2^(x-2) + 1 = 100#

subtract #1# from both sides:
#3*2^(x-2) = 99#

divide by 3 both sides:
#2^(x-2) = 33#

apply #log_2()# to both sides:
#x-2 = log_2(33)#

add #2# to both sides:
#x = log_2(33)+2#

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