How do you solve #3- 2( 5x - 4) > - 9# and #3x > - 4( x - 2)#?

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Answer 1 · 2018-03-17T18:47:32

#3-2(5x-4)> -9# ----------------- #3x> -4(x-2)#
#x<2# -----------------------------------#x>8/7#

Ok so the first one #3-2(5x-4)#
First we distribute the #-2# giving us
#3-10x+8> -9#

We now combine like terms on the left side
#11-10x> -9#

Subtract 11 on both sides giving us
#-10x> -20#

We now divide by #-10# on both sides.
REMEMBER: When dividing by a negative the sign always turn to the other side.

#(-10x)/(-10)< -20/(-10)#

#x<2#

Ok now the second one.
First we distribute the #-4# giving us
#3x> -4x+8#

Now we add #4x# on both sides giving us
#7x>8#

Now we divide #7# on both sides
#(7x)/7>8/7#

#x>8/7#