How do you solve #2x-y=7# and #3x+y=8#?

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Answer 1 · 2015-12-01T10:59:23

#x=3#, #y=-1#

From the first equation, you know that #y=2x-7#. Substitute this expression for #y# in the second equation and get

#3x + (2x-7) = 8#

#5x-7=8#

#5x = 15#

#x=3#

Once #x# is known, we can derive #y# from

#y=2x-7=2*3-7=6-7=-1#