How do you solve #(2x)/(x-3)=(3x)/(x^2-9)+2#?

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How do you solve #(2x)/(x-3)=(3x)/(x^2-9)+2#?

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Answer 1 · 2018-03-14T13:32:20

#x=-6#

Explanation:

#(2x)/(x-3)=(3x)/(x^2-9)+2#
#=>(2x)/(x-3)=(3x)/((x-3)(x+3))+2/1#
#=>((2x)(x+3))/((x-3)(x+3))=(3x(1))/((x-3)(x+3))+(2(x-3)(x+3))/((x-3)(x+3)#
#=>2x(x+3)=3x+2(x^2-9)#
#=>cancel(2x^2)+6x=3x+cancel(2x^2)-18#
#=>6x=3x-18#
#=>3x=-18=>x=-6#

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How do you solve #(2x)/(x-3)=(3x)/(x^2-9)+2#?

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