How do you solve 2x^2+18=0?
1 Answer
Jul 2, 2018
Explanation:
"subtract 18 from both sides"
2x^2=-18
x^2=(-18)/2=-9
x=+-sqrt(-9)=+-3i
"subtract 18 from both sides"
2x^2=-18
x^2=(-18)/2=-9
x=+-sqrt(-9)=+-3i