How do you solve #|-2x+1|<1#?

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How do you solve #|-2x+1|<1#?

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Answer 1 · 2018-03-03T13:58:56

#x>0andx<1#

Explanation:

#|M+N|<##KhArr##M+N<(K)and##M+N>(-K)#
So,
#|-2x+1|<1hArr-2x+1<1and-2x+1>(-1)#
#hArr-2x<1-1and-2x>(-1)-1#
#hArr-2x<0and-2x>(-2)#
Dividing both sides by (-2),
#hArrxcolor(red)(>)0andxcolor(red)(<)1# (ineqalities change)

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How do you solve #|-2x+1|<1#?

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