# How do you solve 2log_3(x+4)=log_3(9)+2?

Dec 17, 2015

I found $x = 5$

#### Explanation:

we can use a little trick and write $2 = {\log}_{3} \left(9\right)$
so you get:
$2 {\log}_{3} \left(x + 4\right) = {\log}_{3} \left(9\right) + {\log}_{3} \left(9\right)$
$\cancel{2} {\log}_{3} \left(x + 4\right) = \cancel{2} {\log}_{3} \left(9\right)$
for the logs to be equal the arguments must be equal so:
$x + 4 = 9$
$x = 5$