How do you solve #2log_3(x+4) - log_3 243 = 2#?

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How do you solve #2log_3(x+4) - log_3 243 = 2#?

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Answer 1 · 2017-01-30T21:34:20

I got: #x=3^(7/2)-4=42.7654#

Explanation:

We use the definition of log to get:
#log_3(243)=5#
so we write:
#2log_3(x+4)-5=2#
#2log_3(x+4)=5+2#
#2log_3(x+4)=7#
#log_3(x+4)=7/2#
#x+4=3^(7/2)#
#x=3^(7/2)-4=42.7654#

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How do you solve #2log_3(x+4) - log_3 243 = 2#?

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