How do you solve #2e^(12x) = 18#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Alexander L. Apr 1, 2016 #ln9/12# Explanation: #2e^(12x)=18# #e^(12x)=9# #ln(e^(12x))=ln(9)# #12xln(e)=ln(9)# #ln(e)=1# So #x=ln(9)/12# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1500 views around the world You can reuse this answer Creative Commons License