2abs(6-2x)-1=7
Isolate the absolute value part of the equation.
2abs(6-2x)-1=color(white)a7
color(white)(aaaaaaa^2)+1color(white)(a)+1color(white)(aaa)Add 1 to both sides
(2abs(6-2x))/2color(white)(a^2a)=color(white)a8/2color(white)(aaa)Divide both sides by 2
abs(6-2x)=4
Solving absolute value problems requires setting up TWO equations. Make the right side of the 2nd equation negative.
color(white)(a^2)6-2x=4color(white)(aaa)andcolor(white)(aaa)6-2x=-4
-6color(white)(aaaaa)-6color(white)(aaaaaa)-6color(white)(aaaaaa^2a)-6color(white)(aa)Subtract 6
(-2x)/-2=(-2)/-2color(white)(aaa)andcolor(white)(aa)(-2x)/-2=(-10)/-2color(white)(aa)Divide by -2
color(white)(aa)x=1color(white)(aaaaaaa)andcolor(white)(aaaaaa)x=5
