How do you solve $2 | 3 - x | + 10 = 5$ $2abs(3-x)+10=5$ ?

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Answer 1 · 2015-04-03T17:11:12

The answer is: $x \in {}$ $x in {}$

If there is only one absolute value operator, leave it alone at a side of the equation first. That makes easier to solve them.

$2 | 3 - x | = - 5$ $2abs(3-x)=-5$

$| 3 - x | = - \frac{5}{2}$ $abs(3-x) = -5/2$

Now we can see that there is no such value of $x$ $x$ to solve this equation since the absolute value operator returns only non-negative.

The result is: $x \in {}$ $x in {}$

How do you solve 2|3−x|+10=52abs(3-x)+10=5?