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How do you solve #27^(x+2)=3#?

1 Answer

May 23, 2015

#27^(x+2)=3#

#27# can be written as #(3)^3#

the expression now becomes:
#(3)^(3.(x+2)) = (3)^1#

equating exponents:
#3.(x+2) = 1#

#3x+6 = 1#

#x= -5/3#

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