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How do you solve #23^x + 5 = 128#?

1 Answer

Oct 3, 2016

#x = ln(123)/ln(23) = log_23(123)~~1.535#

Explanation:

Using the property that #ln(a^x) = xln(a)#, we have

#23^x+5 = 128#

#=> 23^x = 123#

#=> ln(23^x) = ln(123)#

#=> xln(23) = ln(123)#

#:. x = ln(123)/ln(23) = log_23(123)~~1.535#

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