How do you solve #20^(x^2)=70#? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer CW Dec 16, 2016 #x=+- 1.1909# Explanation: take log of both sides, #log20^(x^2)=log70# #x^2log20=log70# #x^2=log70/log20=1.418182....# #x=+-1.1909# (4 decimal place) Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 1483 views around the world You can reuse this answer Creative Commons License