How do you solve #2^x= 4^(x+1)#?

1 Answer
Don't Memorise
Sep 9, 2015

#color(blue)(x = -2#

Explanation:

#2^x = 4^(x+1)#

We know that #4 = 2^2#

So,
#2^x = 2^(2(x+1))#

#2^color(blue)(x) = 2^color(blue)((2x +2 )#

At this stage as the bases are equal we equate the exponents to find #x#

#x = 2x+2#
#-2 = 2x-x#
#color(blue)(x = -2#

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