# How do you solve 2^x=4^(x+1)?

Jun 17, 2015

color(red)( x = -2

#### Explanation:

2^color(red)(x)=2^(color(red)(2.(x+1)
Here as bases are equal we can equate the respective powers with each other:

$x = 2 \left(x + 1\right)$
$x = 2 x + 2$
color(red)( x = -2