How do you solve #2^x = 30#?

1 Answer
sente
Mar 2, 2016

#x = log_2(30)~~4.907#

Explanation:

We will use the following properties of logarithms:

  • #log(a^x) = xlog(a)#

  • #log_a(a) = 1#

With these, we have

#2^x = 30#

#=>log_2(2^x) = log_2(30)#

#=>xlog_2(2) = log_2(30)#

#=>x(1)=log_2(30)#

#:.x = log_2(30)~~4.907#

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