How do you solve $2|x – 3| - 5 = 9$ ?

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Answer 1 · 2016-06-05T21:27:31

First of all you can have the absolute value on one side and the rest of the numbers on the other:

$2|x-3|-5=9$

$2|x-3|=9+5$

$2|x-3|=14$

$|x-3|=7$

Then, you can remove the absolute value using the $\pm$

$x-3=\pm7$

$x=\pm7+3$

Then the equation is valid for

$x=7+3=10$

and

$x=-7+3=-4$ .

How do you solve 2|x – 3| - 5 = 92|x – 3| - 5 = 9?