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How do you solve #2^(x) + 2^(2x) = 72#?

1 Answer

Jun 22, 2016

#x = 3#

Explanation:

Taking #y = 2^x# we have

#y+y^2=72#

Solving for #y# we get

#{y = -9},{y = 8}#

but #y = 2^x# must be positive then we follow with

#y = 2^x = 8->x = 3#

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